For any AP, the expression for the $n^{t h}$ term is always a ___ expression in $n$ .

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Solution

We know that $n^{t h}$ term of an AP is given by a + (n-1)d where a = first term, d = common difference, $a_{n}$ = $n^{t h}$ term.
Rearranging further a + (n-1)d we get,
$a_{n} = d n + (a - d)$ which is a linear expression in ‘n’. ('a’ and ‘d’ are constants, and the highest power on the variable n is 1)

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