For any event E, $P (E) + P (¯ ¯¯ ¯ E) = 1$ where $¯ ¯¯ ¯ E$ stands for 'not E'. $E$ and $¯ ¯¯ ¯ E$ are called complementary events

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Either

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Neither

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A True
Given any event E, there are only 2 cases possible either E occurs or E does not occur,
which means $P (¯ E) + P (E) = 1$
where $¯ E$ is not $E$
So, the given statement is true.

Suggest Corrections

Similar questions

If E and F are events such that $P (E) = \frac{1}{4},$
$P (F) = \frac{1}{2}$ and $P (E and F)$ $= \frac{1}{8}$ Find
$(i) P (E or F) (ii) P (not E and not F)$

Q. If E and F are events such that P(E) = , P(F) = and P(E and F) = , find:(i) P(E or F), (ii) P(not E and not F).

If E and F are events such that P(E) =, P(F) = and P(E and F) =, find:(i) P(E or F), (ii) P(not E and not F).

Given that E and F are events such that P (E) = 0.6 P (F) = 0.3 and
P $(E \cap F) = 0.2, f i n d (\frac{E}{F}) a n d P (\frac{F}{E}) .$

IF P (E) deonotes the probability of an event E then
(a) P(E) < 0 (b) P(E) > 1 (c) $0 \leq P (E) \leq 1$ (d) $- 1 \leq P (E) \leq 1$

Join BYJU'S Learning Program

For any event E, P(E)+P(¯¯¯¯E)=1 where ¯¯¯¯E stands for 'not E'. E and ¯¯¯¯E are called complementary events

The correct option is A TrueGiven any event E, there are only 2 cases possible either E occurs or E does not occur, which means P(¯E)+P(E)=1where ¯E is not ESo, the given statement is true.

For any event E, $P (E) + P (¯ ¯¯ ¯ E) = 1$ where $¯ ¯¯ ¯ E$ stands for 'not E'. $E$ and $¯ ¯¯ ¯ E$ are called complementary events

The correct option is A True
Given any event E, there are only 2 cases possible either E occurs or E does not occur,
which means $P (¯ E) + P (E) = 1$
where $¯ E$ is not $E$
So, the given statement is true.