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Question

For any four points P,Q,R,S,
|PQ×RSQR×PS+RP×QS| is equal to 4 times the area of the triangle

A
PQR
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B
QRS
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C
PRS
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D
PQS
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Solution

The correct option is B QRS

Let a,b,c,d be the position vectors of points P,Q,R and S respectively.
Then, PQ×RS=(ba)×(dc)=b×db×c+d×ac×aQR×PS=(cb)×(da)=c×dc×ab×da×bRP×QS=(ac)×(db)=a×da×bc×db×cPQ×RSQR×PS+RP×QS=b×db×c+d×ac×ac×d+c×a+b×d+a×b+a×da×bc×db×c=2(b×d)2(b×c)2(c×d)=2{b×d+c×b+d×c}
=2(QS×QR)=4 area of QSR


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