Question

For any function $f\left(x\right)=3^x,$ arrange the following values of $f\left(x\right)$ in ascending order.

Answer 1

Given $f\left(x\right)=3^x,$
We know for any exponential function of the form $f\left(x\right)=a^x,a>1$.
For any two numbers $x_1\&x_2,$
$\text{if}{a}^{x_1}>a^{x_2}\Rightarrow x_1>x_2$

Thus, using this observation, we can arrange the function values as:
$f(-2.5)<f\left(0\right)<f\left(0.2\right)<f\left(2\right)<f\left(3.2\right)$