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Question

For any positive integer m, n ( with nm)=nCm.
(nm)+(n1m)+(n2m)+...+(mm)=

A
(n+1m+1)
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B
(nm+1)
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C
(nm)
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D
(n1m)
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Solution

The correct option is D (n+1m+1)
(mn)+(m+1m)+(m+2m)+...+(nm)
=(m+1m+1)+(m+1m)+(m+2m)+...+(nm)
=(m+2m+1)+(m+2m)+...+(nm)
=(m+3m+1)+(m+3m)+...+(nm)
...................................
=(nm+1)+(nm)=(n+1m+1)
Thus, (nm)+(n1m)+(n2m)+...+(mm)=(n+1m+1)

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