CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For any positive integer m, n ( with nm)=nCm.
(nm)+(n1m)+(n2m)+...+(mm)=

A
(n+1m+1)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(nm+1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(nm)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(n1m)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D (n+1m+1)
(mn)+(m+1m)+(m+2m)+...+(nm)
=(m+1m+1)+(m+1m)+(m+2m)+...+(nm)
=(m+2m+1)+(m+2m)+...+(nm)
=(m+3m+1)+(m+3m)+...+(nm)
...................................
=(nm+1)+(nm)=(n+1m+1)
Thus, (nm)+(n1m)+(n2m)+...+(mm)=(n+1m+1)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Combinations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon