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Question

Question 4
For any positive integer n, prove that n3n is divisible by 6.

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Solution

Let a=n3n
=n(n21)=n(n+1)(n1)
This is the product of three consecutive positive integers. We know that the product of three consecutive positive integers is divisible by 2 as well as 3. So, it must be divisible by 6.

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