For any positive real number x, write the value of
{(xa)b}1ab{(xb)c}1bc{(xc)a}1ca
{(xa)b}1ab{(xb)c}1bc{(xc)a}1ca=(xab)1ab.(xbc)1bc.(xca)1ca=xabab.xbcbc.xcaca=x1×x1×x1=x×x×x=x3