For any quadratic equation ax2+bx+c=0,a,b,c∈Q,a≠0. The roots will be irrational and distinct if Discriminant and a perfect square.
A
D=0
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B
D>0
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C
is not
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D
is
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Solution
The correct option is C is not Given quadratic equation: ax2+bx+c=0.
The equation has irrational and distinct roots.
Since, the roots of the equation are given by: x=−b±√b2−4ac2a
The roots will be irrational iff: b2−4ac>0 and is not a perfect square.