For any real number $a,$ the value of modulus of $a$ or $| a |$

= 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\geq 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

< 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\geq 0$
We know the modulus function will return a non - negative value for any input.
This means $| a | \geq 0 \forall a \in R .$

Suggest Corrections

Similar questions

For any positive real number x, write the value of

${(x^{a})^{b}}^{\frac{1}{a b}} {(x^{b})^{c}}^{\frac{1}{b c}} {(x^{c})^{a}}^{\frac{1}{c a}}$

Q. For any positive real number x, find the value of

{(\frac{x^{a}}{x^{b}})}^{a + b} \times {(\frac{x^{b}}{x^{c}})}^{b + c} \times {(\frac{x^{c}}{x^{a}})}^{c + a}

For any positive real number x, find the value of ${(\frac{x^{a}}{x^{b}})}^{a + b} \times {(\frac{x^{b}}{x^{c}})}^{b + c} \times {(\frac{x^{c}}{x^{a}})}^{c + a}$

For any two complex numbers $z_{1} a n d z_{2}$ and two real numbers, a, b, find the value of $| a z_{1} - b z_{2} |^{2} + | b z_{1} + b z_{2} |^{2} .$

Q. For any positive real number x, write the value of

{\{{(x^{a})}^{b}\}}^{\frac{1}{a b}} {\{{(x^{b})}^{c}\}}^{\frac{1}{b c}} {\{{(x^{c})}^{a}\}}^{\frac{1}{c a}}

Join BYJU'S Learning Program

For any real number a, the value of modulus of a or |a|

The correct option is B ≥0We know the modulus function will return a non - negative value for any input. This means |a|≥0 ∀ a∈R.

For any real number $a,$ the value of modulus of $a$ or $| a |$

The correct option is B $\geq 0$
We know the modulus function will return a non - negative value for any input.
This means $| a | \geq 0 \forall a \in R .$