Question

For any real number $x,$ the inequality satisfying $\frac{-x}{4}-3<-x$ is

Answer 1

Given: $\frac{-x}{4}-3<-x$
Multiplying both sides by $4,$ we get:
$(\frac{-x}{4}-3)\times 4<-4x\Rightarrow -x-12<-4x\Rightarrow 3x<12\Rightarrow \frac{3x}{3}<\frac{12}{3}\Rightarrow x<4\Rightarrow x\in (-\infty ,4)$