Question

For any $\theta$, state the value of:
${\sin }^2\theta +{\cos }^2\theta$

Answer 1

${\sin }^2\theta +{\cos }^2\theta$
= $(\frac{P}{H}{)}^2+(\frac{B}{H}{)}^2$ where P is Perpendicular, B is Base and H is Hypotenuse
= $\frac{P^2+B^2}{H^2}$
= $\frac{H^2}{H^2}$ (using Pythagoras Theorem $H^2=P^2+B^2$)
= $1$