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Question

For any three vectors a, b, c the value of a.b+c×a+ b+ c is _____________.

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Solution

For any three vectors a, b, c ;
a·b+c×a+b+c
=a·b+c×a+b+c×b+c By distributive law=a·b+c×a+0 x×x=0=a·b+c×a=a·b×a+c×a By distributive law=a·b×a+a.c×a=0+0 Since two vectors are same a·b+c×a+b+c=0

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