For any three vectors →a,→band→c, [→a+→b→b+→c→c+→a]=.
A
[→a→b→c]
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B
2[→a→b→c]
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C
4[→a→b→c]
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D
None of these
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Solution
The correct option is B2[→a→b→c] (→a+→b→b+→c→c+→a)=(→a+→b).{(→b+→c)×(→c+→a)}=(→a+→b){→b×→c+→b×→a+→c×→c+→c×→a}=(→a+→b).(→b×→c+→b×→a×→c×→a)=→a.(→b×→c)+→a.(→b×→a)+→a.(→c×→a)+→b(→b×→c)+→b.(→b×→a)+→b(→c×→a)=(abc)+0+0+0+0+(bca)=(abc)+(abc)=2(abc)Hence,optionBiscorrectanswer.