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Question

For any two complex numbers z1 and z2, if |z1|=2 and |z2|=3, then the value of |3z1+2z2|2+|3z12z2|2 is

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Solution

|3z1+2z2|2+|3z12z2|2
[|z1z2|2=|z1|2+|z2|22Re(z1¯¯¯¯¯z2),|z1+z2|2=|z1|2+|z2|2+2Re(z1¯¯¯¯¯z2)]=9|z1|2+4|z2|2+Re(6z1¯¯¯¯¯z2)+9|z1|2+4|z2|2Re(6z1¯¯¯¯¯z2)=18|z1|2+8|z2|2=18×22+8×32 (|z1|=2,|z2|=3)=144

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