For any two sets A and B, prove by using of properties of sets that (A∪B)−A=B−A, Also,
verify this result by taking example.
We have
LHS=(A∪B)−A=(A∪B)∩A′=(A∪B)∪(B∩A)=ϕ∪(B∩A′)=B∩A′=B−A=RHSLet A ={1,2,4,5,6}andB={3,5,6,8}Now, LHS=(A∪B)−A={1,2,4,5,6}∪{3,5,6,8}−{1,2,4,5,6}={1,2,3,4,5,6,8}−{1,2,4,5,6}={3,8}and RHS=B−A={3,5,6,8}−1,2,4,5,6={3,8}∴LHS = RHS