For any two sets A and B, prove that : $A' - B' = B - A$

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Solution

$LHS = A' - B' = A' \cap (B')' [∵ C - D = C \cap D'] = A' \cap B = B \cap A' = B - A [∵ C \cap D' = C - D] RHS = B - A$

So, LHS = RHS

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For any two sets A and B , prove that :

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