For any two sets A and B, show that the following statements are equivalent :
(i) A⊂B (ii) A−B=ϕ
(iii) A∪B=B (iv) A∩B=A.
(i) In order to show that the following four statements are equivalent, we need to show that (1) ⇒ (2), (2) ⇒ (3), (3) ⇒ (4) and (4) ⇒ (1)
We first show that (1) ⇒ (2)
We assume that A⊂B, and use this to show that A−B=ϕ
Now A - B = {x ϵA:x /ϵB}, As A⊂B,
∴ Each element of A is an element of B,
∴ A - B = ϕ
Hence, we have proved that (1) ⇒ (2).
(ii) We now show that (2) ⇒ (3)
So assume that A - B = ϕ
To show A∪B=B
A - B = ϕ
Every element of A is an element of B
[∴A−B=ϕ only when there is some element in A which is not in B]
So A⊂B and therefore A∪B=B
So (2) ⇒ (3) is true.
(iii) A∪B=B
We now show that (3) ⇒ (4)
Assume that A∪B=B
To show : A∩B=A
∵A∪B=B
∴A⊂B and so A∩B=A
So (3) ⇒ (4) is true.
(iv) A∩B=A
Finally, we show that (4) ⇒ (1), which will prove the equivalence of the four statements.
So, assume that A∩B=A
To show : A⊂B
∵A∩B=A, thereore A⊂B and
so (4) ⇒ (1) is true.
Hence, (1) ⇒ (2) ⇔ (3) ⇔ (4).