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B
n(A)−n(A∩B)
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C
n(B)−n(A∩B)
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D
n(B)+n(A∩B)
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Solution
The correct option is Cn(B)−n(A∩B) For any two sets A&B, we know the relation: A−B=A−(A∩B) ⇒n(A−B)=n(A)−n(A∩B)
Similarly, B−A=B−(A∩B) ⇒n(B−A)=n(B)−n(A∩B)