For any two sets $A & B; n (A - B) =$ $and n (B - A) =$

n (A) + n (A \cap B)

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n (A) - n (A \cap B)

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n (B) - n (A \cap B)

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n (B) + n (A \cap B)

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Solution

The correct option is C $n (B) - n (A \cap B)$
For any two sets $A & B$ , we know the relation:
$A - B = A - (A \cap B)$
$\Rightarrow n (A - B) = n (A) - n (A \cap B)$
Similarly, $B - A = B - (A \cap B)$
$\Rightarrow n (B - A) = n (B) - n (A \cap B)$

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