For any two sets $X & Y$
$X △ Y = Y △ X .$

True

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False

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Solution

The correct option is A True

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Similar questions

X & Y

X △ Y = Y △ X .

⎡ ⎢ ⎣ \begin{matrix} x & y & x + y y & x + y & x x + y & x & y \end{matrix} ⎤ ⎥ ⎦

X & Y,

X △ Y = X,

Y = ϕ .

x^{y} + y^{x} = a^{b}

\frac{d y}{d x} = - [\frac{y x^{y - 1} + y^{x} log y}{x^{y} log x + x y^{x - 1}}]

X & Y; X \cup Y = Y \cup X .

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