For any vector →a, the value of (→a×^i)2+(→a×^j)2+(→a×^k)2 is equal to
A
3→a2
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B
→a2
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C
2→a2
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D
4→a2
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Solution
The correct option is C2→a2 Let →a=x^i+y^j+z^k ⇒→a×^i=z^j−y^k =>(→a×^i)2=y2+z2 Similarly (→a×^j)2=x2+z2 and (→a×^k)2=x2+y2 ∴(→a×^i)2+(→a×^j2+(→a×^k)2=2(x2+y2+z2)=2→a2