For Association Van’t Hoff factor is

i = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

i > 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

i < 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

i = 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C i < 1
In association as particles combine each other , final number of particles are less than intial number of particles. So as
Van't hoff factor = $\frac{N o . o f . P a r t i c l e s f i n a l l y i n t h e s o l u t i o n}{N o . o f p a r t i c l e s i n t i a l l y t a k e n} < 1.$

Suggest Corrections

Similar questions

60 %

C H_{3} C O O H

(i)

^{'} x^{'}

i

Join BYJU'S Learning Program