For batching 1:3:6 concrete mix by volume, the ingredients required per bag of 50kg cement, are :
A
70 liters of sand and 120 liters of aggregates
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B
70 kg of sand and 140 liters of aggregates
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C
105 liters of sand and 140 liters of aggregates
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D
105 liters of sand and 210 liters of aggregates
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Solution
The correct option is D105 liters of sand and 210 liters of aggregates Volume of one beg cement =0.035cum.
Hence sand aggregates =0.035×6=0.21cum =0.035×3=0.105cum 1cum=1000Lt
So sand =0.1.5×1000=105Lt
and aggregates =105×2=210Lt