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Question

For batching 1:3:6 concrete mix by volume, the ingredients required per bag of 50 kg cement, are :

A
70 liters of sand and 120 liters of aggregates
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B
70 kg of sand and 140 liters of aggregates
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C
105 liters of sand and 140 liters of aggregates
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D
105 liters of sand and 210 liters of aggregates
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Solution

The correct option is D 105 liters of sand and 210 liters of aggregates
Volume of one beg cement =0.035 cum.
Hence sand aggregates =0.035×6=0.21 cum
=0.035×3=0.105 cum
1 cum=1000 Lt
So sand =0.1.5×1000=105 Lt
and aggregates =105×2=210 Lt

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