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Question

For CaCO3(s)CaO(s)+CO2(g) at 977oC, ΔH=174 kJ/mol; then ΔE is:

A
160 kJ
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B
163.6 kJ
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C
186.4 kJ
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D
180 kJ
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Solution

The correct option is B 163.6 kJ
CaCO3(s)CaO(s)+CO2(g) Δng=10=1

T=977=977+273=1250K

ΔE=ΔHΔngRT

(=174×(103)1(8.314)×(1250)) J

=163.6 kJ

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