For CaCO3(s)--CaO(s)+CO2(g) at 977°C ∆H=174KJ/mol ;then ∆E is

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Solution

∆H = ∆E + ∆nRT
where, Δn is product - reactant moles for gases only.

For CaCO3(s)--CaO(s)+CO2(g);
Gases (moles) = carbon dioxide moles = 1

R = 8.314 J/moles.K
T= 273 + 977 = 1250 K

∆E = ∆H - ∆nRT
= 174 - (1 x 8.314 x 1250)/1000
= 163.6075 KJ/mol

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C a {C O}_{3} (s) \to C a O (s) + {C O}_{2} (g)

977^{o} C

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1240

1

C a C O_{3} (s) \to C a O (s) + C O_{2} (g)

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