For CE transistor amplifier, the audio signal voltage across the collector resistance of $2 k Ω$ is $4 V$ . If the current amplification factor of the transistor is $100$ and the base resistance is $1 k Ω$ , then the input signal voltage is

5 m V

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10 m V

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20 m V

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30 m V

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Solution

The correct option is C $20 m V$
Given that:
$\frac{I_{α}}{I_{β}} = 100; R_{C} = 1000 Ω$ , $V_{0} = 4 V$
So, $β = \frac{I_{α}}{I_{β}} = 100$
$\Rightarrow V_{g a i n} = \frac{V_{0}}{V_{i}} = β \frac{R_{L}}{R_{C}}$
$\Rightarrow V_{i} = \frac{4 \times 1000}{100 \times 2000} = 0.02 V$ $= 20 m V$

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Similar questions

For a CE-transistor amplifier, the audio signal voltage across the collected resistance of 2 kΩ is 2 V. Suppose the current amplification factor of the transistor is 100, find the input signal voltage and base current, if the base resistance is 1 kΩ.

Q. For CE transistor amplifier, the audio signal voltage across the collector resistance of

2 k Ω

4 V

. If the current amplification factor of the transistor is

100

and the base resistance is

1 k Ω

, then the input signal voltage is

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For CE transistor amplifier, the audio signal voltage across the collector resistance of 2 kΩ is 4 V. If the current amplification factor of the transistor is 100 and the base resistance is 1 kΩ, then the input signal voltage is

The correct option is C 20 mVGiven that: IαIβ=100;RC=1000 Ω, V0=4V So, β=IαIβ=100 ⇒Vgain=V0Vi=βRLRC ⇒Vi=4×1000100×2000=0.02 V=20 mV

For CE transistor amplifier, the audio signal voltage across the collector resistance of $2 k Ω$ is $4 V$ . If the current amplification factor of the transistor is $100$ and the base resistance is $1 k Ω$ , then the input signal voltage is

The correct option is C $20 m V$
Given that:
$\frac{I_{α}}{I_{β}} = 100; R_{C} = 1000 Ω$ , $V_{0} = 4 V$
So, $β = \frac{I_{α}}{I_{β}} = 100$
$\Rightarrow V_{g a i n} = \frac{V_{0}}{V_{i}} = β \frac{R_{L}}{R_{C}}$
$\Rightarrow V_{i} = \frac{4 \times 1000}{100 \times 2000} = 0.02 V$ $= 20 m V$