For circuits used for transporting electric power, a low power factor implies large power loss transmission. Explain?

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Solution

This statement is incorrect. The correct statement is " For circuits used for transporting electric power, a smaller power factor implies large power loss in transmission".

$P = E_{r m s} I_{r m s} c o s ϕ$
$∴$ $I_{r m s} = \frac{P}{E_{r m s} c o s ϕ}$

Hence, current is inversely proportional to the power factor $c o s ϕ$ .

So, a low power factor will imply a large power loss.

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