For combustion of one mole of magnesium in an open container at 300 K and 1 bar pressure- -cH-601-70 kJ mol-1- the magnitude of change in internal energy for the reaction is kJ-Nearest integerGiven - R-8-3 J K-1mol-1

Mg(s)+12O_2(g)⟶ MgO(s) Δ H=Δ U+ Δ n_gRT Δ n_g = 12 601.70=Δ U 12 ( 8.3 ) ( 300 )× 10^ 3 Δ U= 601.70+1.245 Δ U ≃ 600 kJ Magnitude of change in interna ...

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Standard XII

Chemistry

Enthalpy

For combustio...

Question

For combustion of one mole of magnesium in an open container at $300 K$ and 1 bar pressure, $Δ_{c} H^{⊖} = - 601.70 k J m o l^{- 1}$ , the magnitude of change in internal energy for the reaction is ____ kJ.
(Nearest integer)
(Given : $R = 8.3 J K^{- 1} {mol}^{- 1}$ )

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Solution

$M g (s) + \frac{1}{2} O_{2} (g) ⟶ M g O (s)$

$Δ H = Δ U + Δ n_{g} R T$

$Δ n_{g} = - \frac{1}{2}$

$- 601.70 = Δ U - \frac{1}{2} (8.3) (300) \times 10^{- 3}$

$Δ U = - 601.70 + 1.245$

$Δ U ≃ - 600 k J$

Magnitude of change in internal energy is $600 k J$ .

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For combustion of one mole of magnesium in an open container at 300 K and 1 bar pressure, ΔcH⊖=−601.70 kJ mol−1, the magnitude of change in internal energy for the reaction is ____ kJ. (Nearest integer) (Given : R=8.3 J K−1mol−1)

Mg(s)+12O2(g)⟶MgO(s) ΔH=ΔU+ΔngRT Δng=−12 −601.70=ΔU−12(8.3)(300)×10−3 ΔU=−601.70+1.245 ΔU≃−600 kJ Magnitude of change in internal energy is 600 kJ.

For combustion of one mole of magnesium in an open container at $300 K$ and 1 bar pressure, $Δ_{c} H^{⊖} = - 601.70 k J m o l^{- 1}$ , the magnitude of change in internal energy for the reaction is ____ kJ.
(Nearest integer)
(Given : $R = 8.3 J K^{- 1} {mol}^{- 1}$ )

$M g (s) + \frac{1}{2} O_{2} (g) ⟶ M g O (s)$

$Δ H = Δ U + Δ n_{g} R T$

$Δ n_{g} = - \frac{1}{2}$

$- 601.70 = Δ U - \frac{1}{2} (8.3) (300) \times 10^{- 3}$

$Δ U = - 601.70 + 1.245$

$Δ U ≃ - 600 k J$

Magnitude of change in internal energy is $600 k J$ .