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Question

For complete combustion of ethanol, the amount of heat produced as measured in a bomb calorimeter is 1364.47kJmol1 at 25C.

C2H5OH(l)+3O2(g)2CO2(g)+3H2O(l)

Assuming ideality the enthalpy of combustion, ΔcH, for the reaction will be:
[R=8.314Jmol1]

A
1460.50kJmol1
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B
1350.50kJmol1
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C
1366.95kJmol1
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D
1361.95kJmol1
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Solution

The correct option is A 1366.95kJmol1
C2H5OH(l)+3O2(g)2CO2(g)+3H2O(l),

ΔE=1364.47kJ mol1
ΔH=?
T=298K
Δng=1 complete combution

R=8.314J mol1=8.3141000kJ mol1

ΔH=ΔE+PΔV

but, PΔV=ΔngRT

ΔH=ΔE+ΔngRT

ΔH=1364.47+((1)×8.3141000×298)

ΔH=1366.95kJ mol1

Hence, the correct option is C

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