For constructing a triangle with a given base, a base angle and difference between the other two sides, a
The procedure for Triangle Construction 2 is:
1. Draw the base BC of ∆ABC as given and construct ∠XBC of the required measure at B as shown.
2. From the ray, BX cut an arc equal to AB – AC at point P and join it to C as shown
3. Draw the perpendicular bisector of PC and let it intersect BX at point A as shown:
4. Join AC, ∆ABC is the required triangle.
Hence, it is clear that a perpendicular bisector is required in the process.