Question

For constructing an embankment, the soil is transported from a borrow area using a truck which can carry $6m^3$ of soil at a time. The details are as follows.

Property	Borrow area	Truck (loose)	Field (compacted)
Bulk density (g/cc)	1.66	1.15	1.82
Water content (%)	8	6	14

The quantity of soil to be excavated from the borrow pit, in $m^3$ for a compacted earth fill of 100 $m^3$ is

• A. 104 cum
• B. 146 cum
• C. 98 cum
• D. 87 cum

Answer 1

The correct option is A 104 cum



Volume of embankment = 100 $m^3$

Weight of soil in embankment

$=100\times 1.82$

$=182\frac{g}{cc}{m}^3$

Weight of solid in embankment

$W_s=\frac{W}{1+w}$

$=\frac{182}{1+0.14}=159.649\frac{g}{cc}{m}^3$

Weight of solid remains same in borrow pit. Thus, wt. of solid in borrow pit

$=159.649\frac{g}{cc}{m}^3$

Total Weight of soil in borrow pit

$W_s=\frac{W}{1+w}$

$159.649=\frac{W}{1+0.08}$

$W=172.421\frac{g}{cc}{m}^3$

$Volumeofsoilinborrowpit=\frac{172.421}{1.66}$

Volume of soil in borrow pit $=103.868m^3$

Hence the corrent option is (a)