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Question

For constructing ΔLMN exactly identical to ΔABC, the measurements of .


A
LM
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B
MN and LN
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C
LN
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Solution

The correct option is B MN and LN
The lengths of sides MN and LN are sufficient to construct a triangle identical to ΔABC.
Draw MN as the base and with NL as length draw an arc. Now we can draw a line perpendicular to MN, this interests the arc at L. Hence the ΔMNL is constructed using the lengths of a side and a hypotenuse.

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