Question

For construction of parallelogram $ABCD$ such that $AD=4.5$ cm, $AB=5$ cm and $\angle A={70}^o$, steps for its construction is given below in jumbled form. Which would be the third step of construction?

1) Join points $D$ and $B$ with $C$
2) Draw an axis $AX$ and mark $AB=5$ cm on it and draw a ray $AY$ such that $\angle A={70}^o$
3) Mark point $D$ on $AY$ such that $AD=4.5$ cm
4) Draw arcs of radius $5$ cm as centre $D$ and with radius $4.5$ cm as centre $B$ which intersect at point $C$

• A. $2$
• B. $4$
• C. $1$
• D. $3$

Answer 1

Answer: (B)

$4$

$\Rightarrow$ We have to construct parallelogram ABCD, for that we have given steps.

$\Rightarrow$ Fist is draw an axis $AX$ and mark $AB=5cm$ on it and draw a ray $AY$ such that $\angle A={70}^{\circ }$

$\Rightarrow$ Second is mark point $D$ on $AY$ such that $AD=4.5cm$

$\Rightarrow$ $3^{rd}$ step is : -

$\Rightarrow$ Draw arcs of radius $5cm$ as a center $D$ and with radius $4.5cm$ as center $B$ which intersect at point $C$.