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Types of Redox Reactions

For decolouri...

Question

For decolourisation of $1.5$ moles of ${K M n O}_{4}$ in acidic medium the moles of $H_{2} O_{2}$ requires $:$

\frac{3}{2}

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\frac{9}{4}

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\frac{15}{4}

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\frac{21}{4}

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Solution

The correct option is B $\frac{9}{4}$
$2 K M n O_{4} + 3 H_{2} O_{2} \to 2 M n O_{2} + 3 O_{2} + 2 K O H + 2 H_{2} O$
$2$ moles of $K M n O_{4} \equiv 3$ moles of $H_{2} O_{2}$
$∴ 1.5$ moles of $K M n O_{4} \equiv \frac{3 \times 1.5}{2}$ moles of $H_{2} O_{2}$
$\equiv \frac{9}{4}$ moles of $H_{2} O_{2}$

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