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Balancing Redox Equations

For decolouri...

Question

For decolourization of 1 mole of $K M n O_{4}$ , the moles of $H_{2} O_{2}$ required is

\frac{1}{2}

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\frac{3}{2}

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\frac{5}{2}

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\frac{7}{2}

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Solution

The correct option is C $\frac{5}{2}$
$2 K M n O_{4} + 3 H_{2} S O_{4} \to K_{2} S O_{4} + 2 M n S O_{4} + 3 H_{2} O + 5 O$
$\frac{5 H_{2} O_{2} + 5 O \to 5 H_{2} + 5 O_{2}}{2 K M n O_{4} + 3 H_{2} S O_{4} + 5 H_{2} O_{2} \to K_{2} S O_{4} + 2 M n S O_{4} + 8 H_{2} O + 5 O_{2}}$

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