Question

For $4{NH}_3\left(g\right)+5O_2\left(g\right)\to 4NO\left(g\right)+6H_{2}O\left(g\right)$, how many moles of ${NH}_3$ are needed to produce $2.513$ moles of $NO$?

• A. $2.294$
• B. $36.51$
• C. $1.409$
• D. $25.3$
• E. $2.513$

Answer 1

The correct option is E $2.513$

As per the balanced chemical equation, 4 moles of $N{H}_3$ are needed to produce 4 moles of $NO$.
Hence, $2.513\times \frac{4}{4}=2.513$ moles of $N{H}_3$ are needed to produce 2.513 moles of $NO$.