For $4 {N H}_{3} (g) + 5 O_{2} (g) \to 4 N O (g) + 6 H_{2} O (g)$ , if you begin with 16.00 g ammonia and excess oxygen, how many grams of water will be obtained?

2.294

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36.51

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1.409

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25.3

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2.513

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Solution

The correct option is C 25.3
The molecular weights of ammonia and water are 17 g/mole and 18 g/mole respectively.
4 moles of ammonia gives 6 moles of water.
$4 \times 17 = 68$ g of ammonia will give $6 \times 18 = 108$ g of water.
16.00 g of ammonia will give $16.00 \times \frac{108}{68} = 25.3$ g of water.

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