Question

For $\Delta ABC$ and $\Delta DEF,\angle A={47}^o,\angle E={53}^o$ and $AB=DE=16cm$. $\angle A=\angle D$ and $\angle B=\angle E$, then $\angle C=$..............

• A. ${47}^o$
• B. ${53}^o$
• C. ${80}^o$
• D. ${100}^o$

Answer 1

The correct option is C ${80}^o$

For $\Delta ABC$ and $\Delta DEF$
$\angle A=\angle D,\angle B=\angle E$ and $AB=DE$
$\therefore$ According to A.S.A condition for congruence,
$\Delta ABC\cong \Delta DEF$
$\angle A=\angle D={47}^o$
$\angle B=\angle E={53}^o$
$\angle C=\angle F$
$\therefore \angle D+\angle E+\angle F=\angle A+\angle B+\angle C={180}^o$
$\therefore \angle C={180}^o-{100}^o$
$\therefore \angle C={80}^o$