Question

For $\Delta ABC$ and $\Delta DEF$, $\angle B=\angle D={90}^o$, $AC=EF$ and $AB=ED$. Then $\Delta ABC\cong$..........

• A. $\Delta EDF$
• B. $\Delta DEF$
• C. $\Delta EFD$
• D. $\Delta FED$

Answer 1

Answer: (A)

$\Delta EDF$

For $\Delta ABC$ and $\Delta DEF$,

$\angle B=\angle D={90}^o$, $AC=EF$ and $AB=ED$
$\therefore$ According to R.H.S condition for congruence, both triangles are
$\therefore \Delta ABC\cong \Delta EDF$