For ${log}_{2} | 4 - 5 x | > 2$ , the correct set of $x$ is given by?

x < 0

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x > 0

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x < \frac{8}{5}

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x > \frac{8}{5}

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Solution

The correct options are
A $x < 0$
D $x > \frac{8}{5}$
${log}_{2} | 4 - 5 x | > 2$
$\Rightarrow | 4 - 5 x | > 4$
$\Rightarrow 4 - 5 x > 4$ and $4 - 5 x < - 4$
Therefore, $x < 0$ and $x > \frac{8}{5}$

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