For r=0,1,2,3,...,10, let Ar,Br,Crdenote respectively the coefficient of xrin the expansions of (1+x)10,(1+x)20 and (1+x)30. Then ∑10r=1Ar(B10Br−C10Ar) is equal to
A
B10−C10
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B
A10(B210)−C10A10
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C
0
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D
C10−B10
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Solution
The correct option is CC10−B10 Ar =coefficient of xr in (1+x)10=10Cr Br =coefficient of xr in (1+x)20=20Cr Cr=coefficient of xr in (1+x)30=30Cr ∴∑10r=1Ar(B10Br−C10Ar) =∑10r=1ArB10Br−∑10r=1ArC10Ar =∑10r=110Cr20Cr20Cr−∑10r=110Cr30C1010Cr =∑10r=110C10−r20C1020Cr−∑10r=110C10−r30C1010Cr =20Cr∑10r=110C10−r20Cr−30C10∑10r=110C10−r10Cr =20C10(30C10−1)−30C10(20C10−1) =30C10−20C10=C10−B10