For sin -1x-cos-1y-1z- t2-2- t-3- then the value of cos -1min x-y-z is-

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Properties Derived from Trigonometric Identities

For sin -1x...

Question

For ${sin}^{- 1} x + {cos}^{- 1} y + {sec}^{- 1} z \geq t^{2} - \sqrt{2 π} t + 3 π$ , then the value of ${cos}^{- 1} (m i n {x, y, z})$ is,

0

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\frac{π}{2}

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π

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\frac{π}{3}

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Similar questions

{sin}^{- 1} x + {cos}^{- 1} y + {sec}^{- 1} z \geq t^{2} - \sqrt{2 π} t + 3 π

x + y + z

{sin}^{- 1} x + {cos}^{- 1} y + {sec}^{- 1} z \geq t^{2} - \sqrt{2 π} t + 3 π

{cos}^{- 1} (cos 5 t^{2})

If $s i n^{- 1} x + s i n^{- 1} y = \frac{π}{2}$ ,then $c o s^{- 1} x + c o s^{- 1} y$ is equal to

{s i n}^{- 1} x, {c o s}^{- 1} x, {t a n}^{- 1} x

{t a n}^{- 1} x + {t a n}^{- 1} y = {t a n}^{- 1} \frac{x + y}{1 - x y}

x y < 1

π + {t a n}^{- 1} \frac{x + y}{1 - x y}

x y > 1

{c o s}^{- 1} p + {c o s}^{- 1} q + {c o s}^{- 1} r = π

p^{2} + q^{2} + r^{2} + 2 p q r = 1

{s i n}^{- 1} x + {s i n}^{- 1} y + {s i n}^{- 1} z = π

x^{4} + y^{4} + z^{4} + 4 x^{2} y^{2} z^{2} = 2 (x^{2} y^{2} + y^{2} z^{2} + z^{2} x^{2})

{t a n}^{- 1} x + {t a n}^{- 1} y + {t a n}^{- 1} z = π

π / 2

x + y + z = x y z

x y + y z + z x = 1

c o s^{- 1} x + c o s^{- 1} y + c o s^{- 1} z = π

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