For each n Є N, n (n + 1) (2n + 1) is divisible by:
5
11
6
7
P(1) = (1) (1+1)(2(1)+1) = (1) (2)(3) = 6 So, n (n + 1) (2n + 1) is divisible by 6
For each n Є N, 72n + 16n – 1 is divisible by:
The sum of (n-1) terms of 1+(1+3)+(1+3+5)+.............is