For each n ∈ N, the correct statement is

$2^{n}$ < n

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$n^{2}$ > 2n

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$n^{4}$ < $10^{n}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$2^{3 n}$ > 7n + 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$n^{4}$ < $10^{n}$

Let n = 1, then option (a), (b) and (d)

eliminated. Only option (c) satisfied.

Suggest Corrections

Similar questions

n ϵ N

For every natural number n, n $(n^{2} - 1)$ is divisible by

n \in N

n (n^{2} - 1)

10^{n} - (5 + \sqrt{7})^{n}

2^{n + 2}

n ϵ N, 10^{2 n + 1} + 1

Join BYJU'S Learning Program