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Byju's Answer
Standard XII
Chemistry
Potassium Dichromate
For each of t...
Question
For each of the following reaction in acidic solution, predict the products and write the net balanced ionic equation :
C
r
2
+
(
a
q
)
+
O
2
(
g
)
→
A
C
r
2
+
(
a
q
)
+
O
2
(
g
)
+
H
+
(
a
q
)
→
3
C
r
4
+
(
a
q
)
+
H
2
O
(
l
)
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B
2
C
r
2
+
(
a
q
)
+
O
2
(
g
)
+
2
H
+
(
a
q
)
→
2
C
r
3
+
(
a
q
)
+
2
H
2
O
(
l
)
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C
4
C
r
2
+
(
a
q
)
+
O
2
(
g
)
+
4
H
+
(
a
q
)
→
4
C
r
3
+
(
a
q
)
+
2
H
2
O
(
l
)
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None of these
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Solution
The correct option is
C
4
C
r
2
+
(
a
q
)
+
O
2
(
g
)
+
4
H
+
(
a
q
)
→
4
C
r
3
+
(
a
q
)
+
2
H
2
O
(
l
)
Suggest Corrections
0
Similar questions
Q.
Consider a galvanic cell using solid
C
u
and
F
e
metals with their corresponding solutions.
What is the
E
∘
c
e
l
l
?
Standard Potential (V)
Reduction Half-Reaction
2.87
F
2
(
g
)
+
2
e
−
→
2
F
−
(
a
q
)
1.51
M
n
O
−
4
(
a
q
)
+
8
H
+
(
a
q
)
+
5
e
−
→
M
n
2
+
(
a
q
)
+
4
H
2
O
(
l
)
1.36
C
l
2
(
a
q
)
+
3
e
−
→
2
C
l
−
(
a
q
)
1.33
C
r
2
O
2
−
7
(
a
q
)
+
14
H
+
(
a
q
)
+
6
e
−
→
2
C
r
3
+
(
a
q
)
+
7
H
2
O
(
l
)
1.23
O
2
(
g
)
+
4
H
+
(
a
q
)
+
4
e
−
→
2
H
2
O
(
l
)
1.06
B
r
2
(
l
)
+
2
e
−
→
2
B
r
−
(
a
q
)
0.96
N
O
−
3
(
a
q
)
+
4
H
+
(
a
q
)
+
3
e
−
→
N
O
(
g
)
+
H
2
O
(
l
)
0.80
A
g
+
(
a
q
)
+
e
−
→
A
g
(
s
)
$
0.77
F
e
3
+
(
a
q
)
+
e
−
→
F
e
2
+
(
a
q
)
0.68
O
2
(
g
)
+
2
H
+
(
a
q
)
+
2
e
−
→
H
2
O
2
(
a
q
)
0.59
M
n
O
−
4
(
a
q
)
+
2
H
2
O
(
l
)
+
3
e
−
→
M
n
O
2
(
s
)
+
4
O
H
−
(
a
q
)
0.54
I
2
(
s
)
+
2
e
−
→
2
I
−
(
a
q
)
0.40
O
2
(
g
)
+
2
H
2
O
(
l
)
+
4
e
−
→
4
O
H
−
(
a
q
)
0.34
C
u
2
+
(
a
q
)
+
2
e
−
→
C
u
(
s
)
0
2
H
+
(
a
q
)
+
2
e
−
→
H
2
(
g
)
−
0.28
N
i
2
+
(
a
q
)
+
2
e
−
→
N
i
(
s
)
−
0.44
F
e
2
+
(
a
q
)
+
2
e
−
→
F
e
(
s
)
−
0.76
Z
n
2
+
(
a
q
)
+
2
e
−
→
Z
n
(
s
)
−
0.83
2
H
2
O
(
l
)
+
2
e
−
→
H
2
(
g
)
+
2
O
H
−
(
a
q
)
1.66
A
l
3
+
(
a
q
)
+
3
e
−
→
A
l
(
s
)
−
2.71
N
a
+
(
a
q
)
+
e
−
→
N
a
(
s
)
−
3.05
L
i
+
(
a
q
)
+
e
−
→
L
i
(
s
)
Q.
Consider a spontaneous electrochemical cell between
C
u
and
A
l
. Predict what would happen if excess concentrated
N
a
O
H
were added to the cell with copper ions and a precipitate forms.
Standard Potential (V)
Reduction Half-Reaction
2.87
F
2
(
g
)
+
2
e
−
→
2
F
−
(
a
q
)
1.51
M
n
O
−
4
(
a
q
)
+
8
H
+
(
a
q
)
+
5
e
−
→
M
n
2
+
(
a
q
)
+
4
H
2
O
(
l
)
1.36
C
l
2
(
a
q
)
+
3
e
−
→
2
C
l
−
(
a
q
)
1.33
C
r
2
O
2
−
7
(
a
q
)
+
14
H
+
(
a
q
)
+
6
e
−
→
2
C
r
3
+
(
a
q
)
+
7
H
2
O
(
l
)
1.23
O
2
(
g
)
+
4
H
+
(
a
q
)
+
4
e
−
→
2
H
2
O
(
l
)
1.06
B
r
2
(
l
)
+
2
e
−
→
2
B
r
−
(
a
q
)
0.96
N
O
−
3
(
a
q
)
+
4
H
+
(
a
q
)
+
3
e
−
→
N
O
(
g
)
+
H
2
O
(
l
)
0.80
A
g
+
(
a
q
)
+
e
−
→
A
g
(
s
)
$
0.77
F
e
3
+
(
a
q
)
+
e
−
→
F
e
2
+
(
a
q
)
0.68
O
2
(
g
)
+
2
H
+
(
a
q
)
+
2
e
−
→
H
2
O
2
(
a
q
)
0.59
M
n
O
−
4
(
a
q
)
+
2
H
2
O
(
l
)
+
3
e
−
→
M
n
O
2
(
s
)
+
4
O
H
−
(
a
q
)
0.54
I
2
(
s
)
+
2
e
−
→
2
I
−
(
a
q
)
0.40
O
2
(
g
)
+
2
H
2
O
(
l
)
+
4
e
−
→
4
O
H
−
(
a
q
)
0.34
C
u
2
+
(
a
q
)
+
2
e
−
→
C
u
(
s
)
0
2
H
+
(
a
q
)
+
2
e
−
→
H
2
(
g
)
−
0.28
N
i
2
+
(
a
q
)
+
2
e
−
→
N
i
(
s
)
−
0.44
F
e
2
+
(
a
q
)
+
2
e
−
→
F
e
(
s
)
−
0.76
Z
n
2
+
(
a
q
)
+
2
e
−
→
Z
n
(
s
)
−
0.83
2
H
2
O
(
l
)
+
2
e
−
→
H
2
(
g
)
+
2
O
H
−
(
a
q
)
1.66
A
l
3
+
(
a
q
)
+
3
e
−
→
A
l
(
s
)
−
2.71
N
a
+
(
a
q
)
+
e
−
→
N
a
(
s
)
−
3.05
L
i
+
(
a
q
)
+
e
−
→
L
i
(
s
)
Q.
The reaction,
2
H
2
O
(
l
)
→
4
H
+
(
a
q
.
)
+
O
2
(
g
)
+
4
e
−
is?
Q.
Write balanced net ionic equation for the following reactions in acidic solution.
S
2
O
6
2
−
(
a
q
)
+
C
r
2
O
7
2
−
(
a
q
)
→
S
4
O
6
2
−
(
a
q
)
+
C
r
3
+
(
a
q
)
Q.
Using electron-transfer concept, identify the oxidant and reductant in the following redox reactions.
(a)
Z
n
(
s
)
+
2
H
+
(
a
q
)
⟶
Z
n
2
+
(
a
q
)
+
H
2
(
g
)
(b)
2
[
F
e
(
C
N
)
6
]
3
−
(
a
q
)
+
2
O
H
−
(
a
q
)
+
H
2
O
2
(
a
q
)
→
2
[
F
e
(
C
N
)
6
]
4
−
(
a
q
)
+
2
H
2
O
(
l
)
(c)
2
[
F
e
(
C
N
)
6
]
3
−
(
a
q
)
+
2
O
H
−
(
a
q
)
+
H
2
O
2
(
a
q
)
→
2
[
F
e
(
C
N
)
6
]
4
−
(
a
q
)
+
O
2
(
g
)
+
2
H
2
O
(
l
)
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