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Byju's Answer
Standard VI
Mathematics
Factors of a Number
For each pair...
Question
For each pair of numbers, verify that their product = (HCF × LCM).
(i) 87, 145
(ii) 186, 403
(iii) 490, 1155
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Solution
(i) 87 and 145
We have:
87 = 3 × 29
145 = 5 × 29
HCF = 29
LCM = 29 × 15 × 1
= 435
Now, HCF × LCM = 29 × 435 = 12615
Product of the two numbers = 87 × 145 = 12615
∴ HCF × LCM = Product of the two numbers
Verified.
(ii)186 and 403
186 = 2 × 3 × 31
403 = 31 × 13
HCF = 31
LCM = 31 × 13 × 6
= 2418
Now, HCF × LCM = 31 × 2418 = 74958
Product of the two numbers = 186 × 403 = 74958
∴ HCF × LCM = Product of the two numbers
Verified.
(iii) 490 and 1155
490 = 7 × 7 × 2 × 5
1155 = 5 × 7 ×3 × 11
HCF = 7 × 5
= 35
LCM = 7 × 5 ×7 × 2 × 3 × 11
= 16170
Now, HCF × LCM = 35 × 16170 = 565950
Product of the two numbers = 490 × 1155 = 565950
∴ HCF × LCM = Product of the two numbers
Verified.
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For each of the following pairs of numbers, verify the property:
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(iii) 35,40
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