(a) (NH4)2SO4→2NH+4+SO2+4 Thus, the solution will contain ammonium ion and sulfate ion. The concentration of the ammonium ions will be 2×0.25M=0.50M=50×10−2M. The concentration of sulfate ions will be 0.25 M.
(b) Na2CO3→2Na++CO2−3 Thus, the solution will contain sodium ions and carbonate ions. The concentration of sodium ions will be 2×0.123M=0.246M
The concentration of the carbonate ions will be 0.123 M.
(c) HNO3→H++NO−3 Thus, the solution will contain protons and nitrate ions. The concentration of protons and nitrate ions will be 0.056 M each.