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Question

For each tϵR, let [t] be the greatest integer less than or equal to t. Then limx0+x([1x]+[2x]+.....+[15x]).

A
is equal to 120
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B
Does not exist (in R)
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C
Is equal to 0
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D
Is equal to 15
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Solution

The correct option is A is equal to 120
L=limx0+ x[(1x)+...+(15x)]

L=limx0+ x(1x)+x(2x)+....+x(15x)

Take limx0+ x[1x]

let 1x=y

when x0 ,y

L=limy 1yy

Let y=n+p, when n , 0<p<1

limnnn+p

limn11+pn=1

Take limx0+ x[2x]

Let 2x=y,

when x0,y,

limy 2yy=2

limx0+ x[1x]+x[2x]++x[15x]

=1+2+3++15

=n(n+1)2

=15×162

=120

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